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NEW QUESTION: 1
展示を参照してください。

パケットがMaryからRobertに移動するとき、どの3つのデバイスが転送パスを決定するためにパケットの宛先MACアドレスを使用しますか。 （3つ選んでください。）
A. ルーター2
B. ルーター1
C. スイッチ3
D. スイッチ1
E. Hub1
F. スイッチ2
Answer: C,D,F
Explanation:
説明/参照：
Explanation:
スイッチはトラフィックの転送に宛先MACアドレス情報を使用し、ルータは宛先IPアドレス情報を使用します。ローカルエリアネットワークは、ネットワークトラフィックの転送とフィルタリングにレイヤ2スイッチとブリッジを採用しています。スイッチとブリッジは、Open System Interconnect Model（OSI）のデータリンク層で動作します。スイッチとブリッジはレイヤ2で動作するため、OSIのレイヤ1（物理レイヤ）で動作するハブよりもインテリジェントに動作します。スイッチとブリッジはワイヤ上のトラフィックを監視して送信元と宛先のMACアドレスを調べることができるからです。
トラフィックをリッスンできるようになると、スイッチとブリッジはMACアドレステーブルを編集して、ネットワークトラフィックをより適切にフィルタリングして転送することもできます。上記の機能を実現するために、スイッチとブリッジは次のタスクを実行します。
スイッチまたはブリッジによるMACアドレスの学習も同じ方法で行われます。スイッチまたはブリッジは、各ポートに接続されている各デバイスを待ち受けて、送信元MACアドレスを求めて着信フレームをスキャンします。これにより、スイッチ/ブリッジのMACデータベースに登録されているポートマップへのMACアドレスが作成されます。
MACアドレステーブルのもう1つの名前は、連想メモリまたはCAMテーブルです。スイッチまたはブリッジがネットワークトラフィックをリッスンしている場合、各フレームを受信してMACアドレステーブルと比較します。
MACテーブルをチェックすることによって、スイッチ／ブリッジはフレームがどのポートに入ってきたかを決定することができる。フレームがMACテーブルにある場合、フレームはそのポートでのみフィルタリングまたは送信されます。フレームがMACテーブルにないとスイッチが判断した場合、フレームは着信ポートを除くすべてのポートに転送されます。

NEW QUESTION: 2
Refer to the exhibit.

A technician has configured the FastEthernet 0/1 interface on Sw11 as an access link in VLAN 1. Based on the output
from the show vlan brief command issued on Sw12, what will be the result of making this change on Sw11?
A. The hosts in all VLANs on the two switches will be able to communicate with each other.
B. Only the hosts in VLAN 10 and VLAN 15 on the two switches will be able to communicate with each other.
C. Only the hosts in VLAN 1 on the two switches will be able to communicate with each other.
D. Hosts will not be able to communicate between the two switches.
Answer: D
Explanation:
VLANs are local to each switch's database, and VLAN information is not passed between switches without
implementing VLAN Trunk Protocol (VTP). Trunks carry traffic from all VLANs to and from the switch by default but,
can be configured to carry only specified VLAN traffic. Trunk links are required to pass VLAN information between
switches. So Sw11 port should be trunk not access port. Additionally, there are no ports assigned to VLAN 1.

NEW QUESTION: 3
A security administrator has been asked to select a cryptographic algorithm to meet the criteria of a new application. The application utilizes streaming video that can be viewed both on computers and mobile devices. The application designers have asked that the algorithm support the transport encryption with the lowest possible performance overhead. Which of the following recommendations would BEST meet the needs of the application designers? (Select TWO).
A. Use RC4 in Cipher Block Chaining mode
B. Use RC4 with Fixed IV generation
C. Use RC4 with a nonce generated IV
D. Use AES in Electronic Codebook mode
E. Use AES in Counter mode
F. Use AES with cipher text padding
Answer: C,E
Explanation:
In cryptography, an initialization vector (IV) is a fixed-size input to a cryptographic primitive that is typically required to be random or pseudorandom. Randomization is crucial for encryption schemes to achieve semantic security, a property whereby repeated usage of the scheme under the same key does not allow an attacker to infer relationships between segments of the encrypted message.
Some cryptographic primitives require the IV only to be non-repeating, and the required randomness is derived internally. In this case, the IV is commonly called a nonce (number used once), and the primitives are described as stateful as opposed to randomized. This is because the IV need not be explicitly forwarded to a recipient but may be derived from a common state updated at both sender and receiver side. An example of stateful encryption schemes is the counter mode of operation, which uses a sequence number as a nonce.
AES is a block cipher. Counter mode turns a block cipher into a stream cipher. It generates the next keystream block by encrypting successive values of a "counter". The counter can be any function which produces a sequence which is guaranteed not to repeat for a long time, although an actual increment-by-one counter is the simplest and most popular.

NEW QUESTION: 4

A. Option C
B. Option D
C. Option B
D. Option A
Answer: A