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NEW QUESTION: 1
A large multinational B2C Salesforce customer is looking to implement their distributor management application is Salesforce. the application has the following capabilities:
1.Distributor create sales order in salesforce
2.Sales order are based on product prices applicable to their region
3. Sales order are closed once they are fulfilled
4. It is decided to maintain the order in opportunity object
How should the data architect model this requirement?
A. Add custom fields in Opportunity and use triggers to update prices.
B. Create lookup to Custom Price object and share with distributors.
C. Configure price Books for each region and share with distributors.
D. Manually update Opportunities with Prices application to distributors.
Answer: C

NEW QUESTION: 2
Jason, an HIM educator, plans to lecture on department design and the legislative act or AGENCY that was created to ensure that workers have a safe and healthy work environment. He describes which of the following?
A. Labor Management Relations Act
B. OSHA
C. Taft-Hartley Law
D. Wagner Act
Answer: B

NEW QUESTION: 3
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2012-Server gehostet wird.
Die Datenbank enthält zwei Tabellen mit den folgenden Definitionen:

Globale Kunden geben Bestellungen aus mehreren Ländern auf.
Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM Kunden c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANG () ÜBER (TEILUNG NACH Kunden-ID
ORDER BY COUNT (OrderAmount) DESC) AS Rnk
VON Bestellungen
GRUPPE NACH Kunden-ID, Versandland) AS o
ON c.CustomerID = o.CustomerID
Wobei o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM Kunden c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT (OrderAmount) AS OrderAmount
VON Bestellungen
GRUPPE NACH Kunden-ID, Versandland) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
C. SELECT CustomerID, CustomerName, ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK () OVER (PARTITION BY c.CustomerID
ORDER BY COUNT (o.OrderAmount) ASC) AS Rnk
VOM Kunden c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GRUPPE NACH c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WO Rnk = 1
D. SELECT CustomerID, CustomerName, ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName,
Ö. Lieferungsland,
RANG () ÜBER (TEILUNG NACH c. Kunden-ID
BESTELLUNG NACH o. OrderAmount DESC) AS Rnk
VOM Kunden c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GRUPPE NACH c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WO Rnk = 1
Answer: D