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NEW QUESTION: 1
Which statements best describes the following two OSPF commands, which are used to summarize routes?
area 0 range 192.168.110.0 255.255.0.0
summary-address 192.168.110.0 255.255.0.0
A. The area range command specifies the area where the subnet resides and summarizes it to other areas.
The summary-address command summarizes external routes
B. The area range command summarizes subnets for a specific area. The summary-address commandsummaries a subnet for all areas
C. The area range command defines the area where the network resides. The summary-address command enables autosummanzation
D. The area range command defines the area where the network resides. The summary-address command summanzes a subnet for all areas
Answer: A

NEW QUESTION: 2
Click the exhibit.

The switch is not IGMP-snooping/proxy capable. What happens when Host 2 issues an IGMP report to join
a group?
A. Only Router A gets this IGMP report and propagates a PIM join toward the core network.
B. Only Router A gets this IGMP report, but no further action is taken, as Router A is not the PIM DR.
C. Both Router A and Router B get this IGMP report, and both propagate a PIM join toward the core
network.
D. Both Router A and Router B get this IGMP report; Router B propagates a PIM join toward the core
network.
Answer: D

NEW QUESTION: 3

A. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
C. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
G. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: D

NEW QUESTION: 4
情報所有者の主なセキュリティ責任は次のうちどれですか？
A. 情報システム内のデータの整合性の維持
B. 情報分類管理のテスト
C. 情報分類に関連する統制の決定
D. 情報に必要な分類レベルを決定する
Answer: A