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NEW QUESTION: 1
あなたは、Androidモバイルアプリ用のリアルタイムの音声文字変換Al機能を設計しています。この機能は、音声サービスにデータをストリーミングします。
オーディオのシリアル化に使用するオーディオ形式を推奨する必要があります。ソリューションは、クラウドに転送されるデータの量を最小限に抑える必要があります。
何を勧めますか？
A. WAV / PCM
B. MP4a
C. MP3
Answer: C

NEW QUESTION: 2
展示を参照してください。

エンジニアは、SW1とSW2の間のポットチャネルをアクセスポートからトランクに再構成し、SW1のログでこのエラーにすぐに気付きます。
このエラーを解決するコマンドセットはどれですか。
A）

B）

C）

D）

A. オプションB
B. オプションC
C. オプションA
D. オプションD
Answer: A

NEW QUESTION: 3
Refer to the exhibit.

Which two options are two problems that can occur with this configuration? (Choose two)
A. The MPLS path from R1 to R5 becomes unreachable.
B. R1 and R5 are unable to establish an LDP relationship.
C. The label for the R1 loopback address is filtered from other MPLS routers.
D. The label for the R5 loopback address is filtered from other MPLS routers.
E. MPLS traffic from R1 to R5 takes a suboptimal path.
Answer: A,D

NEW QUESTION: 4
If an Ethernet port on a router was assigned an IP address of 172.16.112.1/20, what is the maximum number of hosts
allowed on this subnet?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: C
Explanation:
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1
Add them up and you get 255. Add one for the all zeros option, and the total is 256.
Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each
octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear,
in which case you could conceivably have 255.
The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of
networks are 2