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NEW QUESTION: 1
Which definition is included in a Cisco UC on UCS TRC?
A. server model and local components (CPU, RAM, adapters, local storage) by name only; part numbers are not included because they change over time
B. configuration of virtual-to-physical network interface mapping
C. configuration settings and patch recommendations for VMware software
D. step-by-step procedures for hardware BIOS, firmware, drivers, and RAID setup
E. required RAID configuration, when the TRC uses direct-attached storage
Answer: E
Explanation:
Explanation/Reference:
Explanation:
Definition of server model and local components (CPU, RAM, adapters, local storage) at the orderable part number level.

NEW QUESTION: 2
If an Alcatel-Lucent 7750 LSR receives a labeled packet with a outer label TTL of 250 and an inner label TTL of 251, which of the following statements is true?
A. The packet will be label switched; both the outer label TTL and the inner label TTL will be 249, because they must be the same.
B. The packet will be label switched; both the outer label TTL and the inner label TTL will be 250.
C. The packet will be label switched; the outer label TTL will be 249 and the inner label TTL will be 250.
D. The packet will be label switched; the outer label TTL will be 249 and the inner label TTL will be 251.
Answer: D
Explanation:
Section: Volume A

NEW QUESTION: 3
You evaluate the monthly performance of your portfolio managers against a broad market index. At the end of each year, you add up the number of months in which their performance exceeded that of the market index. If the probability of beating the market index each month, after expenses and sales loads, is
6 5%, what is the mean and variance of the number of months in a year a manager would beat the index?
A. mean = 7.8, variance = 2.73.
B. mean = 8.7, variance = 2.73.
C. mean = 8.7, variance = 3.73.
Answer: A
Explanation:
For this problem, the number of months in a year a manager would beat the index is a binomial random variable with parameters n = 12 and p = 65%. The mean of a binomial distribution is n*p and the variance is n*p*q, where q = 1 - p. Here, we will obtain a mean of 12 * 65% = 7.8, and a variance of 12 * 35% * 65% = 2.73.