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NEW QUESTION: 1
What is the correct command to set the router ID for an OSPFv3 process?
A. router-id FF02::5
B. router-id 2011::1
C. router-id Loopback00
D. router-id 1.2.3.4
Answer: D
Explanation:
Explanation Stub Router ipv6 unicast-routing ipv6 cef ! interface serial 0/0 no ip address ipv6 enable ipv6 address 2001:ABAB::/64 eui-64 ipv6 ospf 1 area 2 ! ipv6 router ospf 1 router-id 3.3.3.3 area 2 stub !
Reference http://www.cisco.com/en/US/tech/tk872/technologies_configuration_example09186a0080b40d8a.s html

NEW QUESTION: 2
開発者は、Webページのログイン画面へのユーザー入力をサニタイズするために、クライアントサイドのJavaScriptコードを実装しました。このコードでは、ユーザー名フィールドには大文字と小文字のみが入力され、パスワードフィールドには6桁のPINのみが入力されます。セキュリティ管理者は、次のWebサーバーログに関心があります。
10.235.62.11 - - [02 / Mar / 2014：06：13：04] "GET
/site/script.php?user=admin&pass=pass%20or%201=1 HTTP / 1.1 "200 5724
このログを考えると、セキュリティ管理者は次のうちどれに関係しており、開発者はどの修正を実装する必要がありますか？
A. セキュリティー管理者は、管理アクセスを得るために使用されている印刷不能文字に関心があり、開発者は印刷不能文字をすべて削除する必要があります。
B. セキュリティ管理者は、誰かが管理者としてログオンする可能性があることを懸念しているため、開発者は強力なパスワードが強制されるようにする必要があります。
C. セキュリティ管理者はSQLインジェクションに関心があり、開発者はサーバーサイドの入力検証を実装するべきです。
D. セキュリティ管理者はXSSに関心があり、開発者はブラウザ側でUnicode文字を正規化する必要があります。
Answer: C
Explanation:
Explanation
The code in the question is an example of a SQL Injection attack. The code '1=1' will always provide a value of true. This can be included in statement designed to return all rows in a SQL table.
In this question, the administrator has implemented client-side input validation. Client-side validation can be bypassed. It is much more difficult to bypass server-side input validation.
SQL injection is a code injection technique, used to attack data-driven applications, in which malicious SQL statements are inserted into an entry field for execution (e.g. to dump the database contents to the attacker).
SQL injection must exploit a security vulnerability in an application's software, for example, when user input is either incorrectly filtered for string literal escape characters embedded in SQL statements or user input is not strongly typed and unexpectedly executed. SQL injection is mostly known as an attack vector for websites but can be used to attack any type of SQL database.

NEW QUESTION: 3
A user has created a VPC with CIDR 20.0.0.0/16. The user has created one subnet with CIDR
20.0.0.0/16 in this VPC. The user is trying to create another subnet with the same VPC for CIDR
20.0.0.1/24. What will happen in this scenario?
A. The VPC will modify the first subnet CIDR automatically to allow the second subnet IP range
B. The second subnet will be created
C. It will throw a CIDR overlaps error
D. It is not possible to create a subnet with the same CIDR as VPC
Answer: C
Explanation:
A Virtual Private Cloud (VPC) is a virtual network dedicated to the user's AWS account. A user can create a subnet with VPC and launch instances inside that subnet. The user can create a subnet with the same size of VPC. However, he cannot create any other subnet since the CIDR of the second subnet will conflict with the first subnet.
http://docs.aws.amazon.com/AmazonVPC/latest/UserGuide/VPC_Subnets.html