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NEW QUESTION: 1
Given the macro definition below, what should be entered into the Name and Arguments fileds to correctly configured the macro?

A. The macro name is sessiontracker and the argument are sectional ,$ JESSIONIDS.
B. The macro name is sessiontracker (2) and the argument are $action ,$JESSIONIDS.
C. The macro name is sessiontracker and the argument are action, JESSION.
D. The macro name is sessiontracker (2) and the action JESSIONID
Answer: D

NEW QUESTION: 2
あなたの会社は5つの主要な事務所を持っています。各事業所にはデータセンターがあります。
Active DirectoryフォレストとExchange Server 2013組織を展開する予定です。各オフィスは別々のActive Directoryサイトとして構成されます。ユーザーメールボックスは各サイトでホストされます。
次の要件を満たすExchange Server 2013の展開戦略を推奨する必要があります。
すべてのメールボックスデータベースに冗長性を提供

送信電子メールメッセージの一時コピーを作成します

ネットワークに展開されているサーバーの数を最小限に抑える

ネットワーク負荷分散（NLB）を使用してクライアントアクセスに冗長性を提供します。

何をお勧めですか？
A. 各サイトに、メールボックスサーバーの役割とクライアントアクセスサーバーの役割の両方がインストールされているサーバーと、クライアントアクセスサーバーの役割がインストールされている別のサーバーを展開します。
B. 各サイトに、メールボックスサーバーの役割とクライアントアクセスサーバーの役割の両方がインストールされた2つのサーバーを展開します。
C. 各サイトに、メールボックスサーバーの役割とクライアントアクセスサーバーの役割の両方がインストールされているサーバーを1つ展開します。
D. 各サイトに、メールボックスサーバーの役割がインストールされているサーバーとクライアントアクセスサーバーの役割がインストールされている2つのサーバーを展開します。
Answer: D
Explanation:
説明/参照：
Explanation:
WNLBはWindowsフェールオーバークラスタリングと互換性がないため、メールボックスDAGも使用されているExchangeサーバーではWNLBを使用できません。 Exchange 2013 DAGを使用していてWNLBを使用する場合は、クライアントアクセスサーバーの役割とメールボックスサーバーの役割を別々のサーバーで実行する必要があります。
参考文献：
https://technet.microsoft.com/ja-jp/library/jj898588(v=exchg.150).aspx

NEW QUESTION: 3

A. Option A
B. Option D
C. Option C
D. Option B
Answer: D

NEW QUESTION: 4
You have a database that contains the following tables:

You need to write a query that returns a list of all customers who have not placed orders.
Which Transact-SQL statement should you run?
A. SELECT c.custid FROM Sales.Customers c LEFT OUTER Sales.Order o ON c.custid = o.custid
B. SELECT c.custid FROM Sales.Customers c INNER JOIN Sales.Order o ON c.custid = o.custid
C. SELECT custid FROM Sales.Customers INTERSECT SELECT custid FROM Sales.Orders
D. SELECT c.custid FROM Sales.Customers c LEFT OUTER JOIN Sales.Order oON c.custid = o.custid WHERE orderid IS NULL
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Inner joins return rows only when there is at least one row from both tables that matches the join condition.
Inner joins eliminate the rows that do not match with a row from the other table. Outer joins, however, return all rows from at least one of the tables or views mentioned in the FROM clause, as long as those rows meet any WHERE or HAVING search conditions. All rows are retrieved from the left table referenced with a left outer join, and all rows from the right table referenced in a right outer join. All rows from both tables are returned in a full outer join.
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx