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NEW QUESTION: 1
An EMC NetWorker customer is implementing a SAN backup solution by configuring four storage nodes.
The customer plans to use a physical library with two drives.
Which NetWorker feature does this environment represent?
A. Standalone device
B. Parallelism
C. Dynamic drive sharing
D. Dedicated storage node
Answer: C

NEW QUESTION: 2
A company receives clickstream data files to Amazon S3 every five minutes. A Python script runs as a cron job once a day on an Amazon EC2 instance to process each file and load it into a database hosted on Amazon RDS. The cron job takes 15 to 30 minutes to process 24 hours of dat a. The data consumers ask for the data be available as soon as possible.
Which solution would accomplish the desired outcome?
A. Increase the size of the instance to speed up processing and update the schedule to run once an hour.
B. Convert the cron job to an AWS Lambda function and schedule it to run once an hour using Amazon CloudWatch events.
C. Convert the cron job to an AWS Lambda function and trigger this new function using a cron job on an EC2 instance.
D. Create an AWS Lambda function that runs when a file is delivered to Amazon S3 using S3 event notifications.
https://docs.aws.amazon.com/lambda/latest/dg/with-s3.html
Answer: D

NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure that the following requirements are met:
Students must be ranked based on their average marks.
If one or more students have the same average, the same rank must be given to these students.
Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
E. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: H
Explanation:
--Burgos - NO
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx