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NEW QUESTION: 1
Which federal computer crime law specifically refers to fraud and related activity in connection with access devices like routers?
A. 18 U.S.C. 2511
B. 18 U.S.C. 1362
C. 18 U.S.C. 1029
D. 18 U.S.C. 2703
Answer: C
NEW QUESTION: 2
From which sources can you copy reference data during the planning process?
A. Actual data
B. Forecast data
C. Treasury cash flow data
D. Previous plans
E. Cash position data
Answer: A,B,D
NEW QUESTION: 3
[A10] Contoso, Ltd., has five offices. The offices are configured as shown in the exhibit. (Click the Exhibit
button.)
Each office has a local connection to the PSTN.
The peak usage statistics are shown in the following table.
Every audio call consumes 100 kilobits per second (Kbps). You plan to replace the PSTN connection with a centralized SIP trunking service. The service will contain a SIP trunk in the Seattle office and a SIP trunk in the Amsterdam office. The solution will use least cost routing. You need to identify the maximum amount of bandwidth that will be used by each SIP trunk. What should you identify?
Exhibit:
Select and Place:
Answer:
Explanation:
Explanation:
http://lync70337.freeforums.org/exam-a-q-indentify-the-maximum-amount-of-bandwidth-t21.html
Since both SEA and ASD have SIP trunk to internet.
NA calls: Redmond 10 *0.5 =5 Seattle: 100*0.8=80 Amsterdam: 50* 0.2=10 Berlin: 20 *0=0 Paris: 20*0.5=10 Total: 105 * 100K = 10,500 kbps
Eu calls: Redmond 10 *0.5 =5 Seattle: 100*0.2=20 Amsterdam: 50* 0.8=40 Berlin: 20 Paris: 20*0.5=10 Total: 95 * 100K = 9,500 kbps
Box 1: 9,500 Kbps Box 2: 9,500 Kbps
Transatlantic calls:
Amsterdam: 10
Berlin: 0
Paris: 10
Seattle: 20
Los Angeles: 5
Total number of transatlantic calls: 45
Total bandwidth needed: 5760 Kbps (45 x 128 kbps)
Amsterdam: Amsterdam+ Berlin+ Paris calls to north America: 50 calls x 20% (calls to N.A) x 128 kbps + + (berlin)+ 20 x50 x 128kbps equals 1280 Kbps + 1280 Kbps equals 2560 Kbps
Seattle: 100 calls x 20% (calls to Europe) x 128 kbps equals 2560 Kbps
NEW QUESTION: 4
Drag and Drop Questions
Match the descriptions on the left with the IKE phases on the right.
Answer:
Explanation:
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