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NEW QUESTION: 1
Which statements best describes the following two OSPF commands, which are used to summarize routes?
area 0 range 192.168.110.0 255.255.0.0
summary-address 192.168.110.0 255.255.0.0
A. The area range command specifies the area where the subnet resides and summarizes it to other areas.
The summary-address command summarizes external routes
B. The area range command defines the area where the network resides. The summary-address command summanzes a subnet for all areas
C. The area range command summarizes subnets for a specific area. The summary-address commandsummaries a subnet for all areas
D. The area range command defines the area where the network resides. The summary-address command enables autosummanzation
Answer: A

NEW QUESTION: 2
Click the exhibit.

The switch is not IGMP-snooping/proxy capable. What happens when Host 2 issues an IGMP report to join
a group?
A. Both Router A and Router B get this IGMP report, and both propagate a PIM join toward the core
network.
B. Only Router A gets this IGMP report and propagates a PIM join toward the core network.
C. Only Router A gets this IGMP report, but no further action is taken, as Router A is not the PIM DR.
D. Both Router A and Router B get this IGMP report; Router B propagates a PIM join toward the core
network.
Answer: D

NEW QUESTION: 3

A. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
C. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
D. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
F. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
H. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: A

NEW QUESTION: 4
情報所有者の主なセキュリティ責任は次のうちどれですか？
A. 情報に必要な分類レベルを決定する
B. 情報システム内のデータの整合性の維持
C. 情報分類に関連する統制の決定
D. 情報分類管理のテスト
Answer: B