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NEW QUESTION: 1
Which of the following is/are true?
I. Assets = Equity + Liabilities
II. Equity = Retained earnings + Dividends Payable
III. Assets + Liabilities = Equity
IV. Assets = Liabilities - Equity
A. II & IV
B. I & II
C. I only
D. III only
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The basic accounting equation states that Assets = Liabilities + Owners' Equity.

NEW QUESTION: 2
DRAG DROP
You use SQL Server 2014 Enterprise Edition.
Your database contains a partitioned table named AuditData. AuditData is partitioned by year. Partition 1 contains data from the year 2010 and prior.
Management has decided to archive all AUDITDATA records from 2010 and prior.
Management wants the records to be removed from the database entirely and provided to the backup team as a zipped text file. The data must no longer reside in the database.
There is very little tolerance for performance degradation in your environment. You need to remove all 2010 and prior data from the AuditData table by using the least amount of system resources possible. Develop the solution by selecting and arranging the required SQL actions in the correct order.
You may not need all of the actions.

Answer:
Explanation:

Explanation:

Note:
- Create a new partitioned table with the partition function you want, and then insert the data from the old table into the new table by using an INSERT INTO...SELECT FROM statement.
- SPLIT RANGE ( boundary_value )
Adds one partition to the partition function. boundary_value determines the range of the new partition, and must differ from the existing boundary ranges of the partition function.
Based on boundary_value, the Database Engine splits one of the existing ranges into two.
Of these two, the one where the new boundary_value resides is considered the new partition.
- BCP can be used top produce the zipped text file.
- Example: plitting a partition of a partitioned table or index into two partitions The following example creates a partition function to partition a table or index into four partitions.
ALTER PARTITION FUNCTION splits one of the partitions into two to create a total of five partitions.
CREATE PARTITION FUNCTION myRangePF1 (int)
AS RANGE LEFT FOR VALUES ( 1, 100, 1000 );
GO
-Split the partition between boundary_values 100 and 1000
-to create two partitions between boundary_values 100 and 500
--and between boundary_values 500 and 1000.
ALTER PARTITION FUNCTION myRangePF1 ()
SPLIT RANGE (500);

NEW QUESTION: 3
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario darstellen. Jede Frage in der Reihe enthält eine eindeutige Lösung, mit der die angegebenen Ziele erreicht werden können. Einige Fragensätze haben möglicherweise mehr als eine richtige Lösung, während andere möglicherweise keine richtige Lösung haben.
Nachdem Sie eine Frage in diesen Abschnitten beantwortet haben, können Sie NICHT mehr darauf zurückkommen. Infolgedessen werden diese Fragen nicht im Überprüfungsbildschirm angezeigt.
Ihr Netzwerk enthält eine Active Directory-Domäne mit dem Namen adatum.com. Die Domäne enthält zwei DHCP-Server mit den Namen Server1 und Server2.
Server1 hat die folgende IP-Konfiguration.

Server2 hat die folgende IP-Konfiguration.

Einige Benutzer geben an, dass sie manchmal aufgrund widersprüchlicher IP-Adressen nicht auf das Netzwerk zugreifen können.
Sie müssen DHCP konfigurieren, um zu vermeiden, dass bereits verwendete Adressen geleast werden.
Lösung: Auf Server1 ändern Sie die EndRange-IP-Adresse des Bereichs.
Erfüllt dies das Ziel?
A. Nein
B. Ja
Answer: B