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NEW QUESTION: 1
Given:

What should statement1, statement2, and statement3, be respectively, in order to produce the result?
Shape: constructor
Square: foo
Shape: foo

A. Option A
B. Option E
C. Option B
D. Option C
E. Option D
Answer: E
Explanation:
Explanation/Reference:
Explanation:
Incorrect answers:
A: Produces
Shape: constructor
Square: constructor
Square: foo
Shape: foo
B: Produces
Shape: constructor
Square: constructor
Square: foo
Square: foo
C: Produces
Shape: constructor
Shape: foo
Square: foo
E: Produces
Shape: constructor
Shape: foo
Shape: foo

NEW QUESTION: 2
Click the Exhibit button.

An administrator has received reports of poor network performance with a virtual machine.
Which task will improve the network performance of this virtual machine?
A. Add a CPU to the virtual machine.
B. Move the virtual machine to another virtual switch.
C. Adjust shares for the virtual NIC on the virtual machine.
D. Traffic-shape this virtual machine.
Answer: B
Explanation:
One way to improve network performance is to move the virtual machine to another virtual switch. Simple and easy. You can then check the affected vswitch for problems.

NEW QUESTION: 3
View the Exhibit and examine the data in the PROJ_TASK_DETAILS table.

The PROJ_TASK_DETAILS table stores information about tasks involved in a project and the relation between them.
The BASED_ON column indicates dependencies between tasks. Some tasks do not depend on the completion of any other tasks.
You need to generate a report showing all task IDs, the corresponding task ID they are dependent on, and the name of the employee in charge of the task it depends on.
Which query would give the required result?
A. SELECT p.task_id, p.based_on, d.task_in_charge FROM proj_task_details p JOIN proj_task_details d ON (p.task_id = d.task_id);
B. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p FULL OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);
C. SELECT p.task_id, p.based_on, d.task_in_charge FROM proj_task_details p JOIN proj_task_details d ON (p.based_on = d.task_id);
D. SELECT p.task_id, p.based_on, d.task_in_charge
FROM proj_task_details p LEFT OUTER JOIN proj_task_details d ON (p.based_on = d.task_id);
Answer: D