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NEW QUESTION: 1
What are two reasons that duplex mismatches can be difficult to diagnose? (Choose two.)
A. The interface displays a connected (up/up) state even when the duplex settings are mismatched.
B. Full-duplex interfaces use CSMA/CD logic, so mismatches may be disguised by collisions.
C. Autonegotiation is disabled.
D. The symptoms of a duplex mismatch may be intermittent.
E. 1-Gbps interfaces are full-duplex by default.
Answer: A,D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 2
次のうちどれが多要素認証のコンポーネントの1つではありませんか？
A. ユーザーが何か
B. ユーザーが知っていること
C. ユーザーが持っているもの
D. ユーザーが送信するもの
Answer: D
Explanation:
説明
多要素認証システムは、ユーザーが送信するものではなく、ユーザーが知っている、持っている、または持っているもので構成されています。多要素認証は、一般にユーザーが知っている、持っている、または持っているもの（バイオメトリクスや機能など）を使用します。

NEW QUESTION: 3
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to retrieve the students who scored the highest marks for each subject along with the marks.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
C. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
D. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
G. SELECT StudentCode AS Code, Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
Answer: D
Explanation:
Explanation/Reference:
Explanation: