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NEW QUESTION: 1
次のようなコードを考えます。

どちらかに当てはまる場合、どの2つのステートメントがコードをコンパイルしますか？ （2つ選んでください。）
A. CycleはMotorCycleクラスによって実装されるインタフェースです。
B. CycleとMotorCycleはどちらもTransportationスーパークラスを拡張したものです。
C. CycleとMotorCycleはどちらもTransportationインタフェースを実装しています。
D. CycleはMotorCycleの抽象スーパークラスです。
E. MotorCycleはCycleのスーパークラスです。
F. MotorCycleはCycleクラスを実装するインタフェースです。
Answer: A,D

NEW QUESTION: 2
あなたは次のクラスを持っています。 （行番号は参照用にのみ記載されています）。

次の要件を満たすには、doOperationメソッドを完了する必要があります。
* AddNumbがoperationNameパラメータとして渡された場合、AddNumb関数が呼び出されます。
* OperationNameパラメータとしてSubNumbが渡された場合、SubNumb関数が呼び出されます。
どのコードを16行目に挿入しますか？ 必要なコードブロックを正しい順序で選択して配置して、ソリューションを開発します。 コードブロックがすべて必要なわけではありません。

Answer:
Explanation:

Explanation
Target 1:

Target 2:

Target 3:

Target 4:

Note:
* target 2:
GetType() is a method you call on individual objects, to get the execution-time type of the object.
Incorrect: typeof is an operator to obtain a type known at compile-time (or at least a generic type parameter).
The operand of typeof is always the name of a type or type parameter - never an expression with a value (e.g. a variable). See the C# language specification for more details.
Reference: What is the difference of getting Type by using GetType() and typeof()?
http://stackoverflow.com/questions/11312111/when-and-where-to-use-gettype-or-typeof

NEW QUESTION: 3
An application receives JSON data in the following format:

The application includes the following code segment. (Line numbers are included for reference only.)

You need to ensure that the ConvertToName() method returns the JSON input string as a
Name object.
Which code segment should you insert at line 10?
A. Return ser.Deserialize<Name>(json);
B. Return ser.ConvertToType (json, typeof (Name));
C. Return ser.Desenalize (json, typeof(Name));
D. Return ser.ConvertToType<Name>(json);
Answer: A