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NEW QUESTION: 1
Which four items are needed to provision a user for Cisco Unified Presence? (Choose four.)
A. voicemail account
B. Client Services Framework device
C. UC service
D. service profile
E. assign user to Cisco Unified Presence node
F. directory number
G. mobility information
Answer: B,C,D,E

NEW QUESTION: 2

A. Option D
B. Option C
C. Option B
D. Option A
Answer: D
Explanation:
Explanation
References:
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NEW QUESTION: 3
Click the Exhibit button.
user@host> monitor traffic interface ge-0/0/3
verbose output suppressed, use <detail> or <extensive> for full protocol decode
Address resolution is ON. Use <no-resolve> to avoid any reverse lookup delay.
Address resolution timeout is 4s.
Listening on ge-0/0/3, capture size 96 bytes
Reverse lookup for 172.168.3.254 failed (check DNS reachability). Other reverse lookup failures will not be reported.
Use <no-resolve> to avoid reverse lockups on IP addresses.
19:24:16.320907 In arp who-has 172.168.3.254 tell 172.168.3.1 19.24:17.322751 In arp who has 172.168.3.254 tell 172.168.3.1 19.24:18.328895 In arp who-has 172.168.3.254 tell
172.168.3.1
19.24:18.332956 In arn who has 172.168.3.254 tell 172.168.3.1
A new server has been set up in your environment. The administrator suspects that the firewall is blocking the traffic from the new server. Previously existing servers in the VLAN are working correctly. After reviewing the logs, you do not see any traffic for the new server.
Referring to the exhibit, what is the cause of the problem?
A. The firewall has a filter enabled to blocktrafficfrom the server.
B. The firewall has been misconfigured with the incorrect routing-instance.
C. The server has been misconfigured with the wrong IP address.
D. The server is in the wrong VLAN.
Answer: B

NEW QUESTION: 4
Given the integer implements comparable:
import java.util.*;
public class SortAndSearch2 {
static final Comparator<Integer> IntegerComparator =
new Comparator<Integer>() {
public int compare (Integer n1, Integer n2) {
return n2.compareTo(n1);
}
};
public static void main(String args[]) {
ArrayList<Integer> list = new ArrayList<>();
list.add (4);
list.add (1);
list.add (3);
list.add (2);
Collections.sort(list, null);
System.out.println(Collections.binarySearch(list, 3));
Collections.sort(list,IntegerComparator);
System.out.println(Collections.binarySearch(list, 3));
}
}
What is the result?
A. 1 2
B. 2 3
C. 2 2
D. 3 2
E. 2 1
Answer: E