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NEW QUESTION: 1

A. Network Topology
B. Cisco Intelligent WAN application
C. traceroute
D. Path Trace
Answer: D
Explanation:
One of the most important features of the APIC-EM controller is the capability to manage policies across the entire network. APIC-EM ACL Analysis and Path Trace provide tools to allow the administrator to analyze and understand ACL policies and configurations. Administrators are hesitant to change ACLs, for fear of breaking them and causing new problems. Together, ACL Analysis and Path Trace enable the administrator to easily visualize traffic flows and discover any conflicting, duplicate, or shadowed ACL entries.

NEW QUESTION: 2
Sarah needs to make a cake and some cookies. The cake requires 3/8 cup of sugar and the cookies require 3/5 cup of sugar. Sarah has 15/16 cups of sugar.
Does she have enough sugar, or how much more does she need?
A. She needs 1/9 of a cup of sugar.
B. She needs 4/19 of a cup of sugar.
C. She needs 1/8 of a cup of sugar.
D. She has enough sugar.
E. She needs 3/80 of a cup of sugar.
Answer: E
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 3
An administrator configures a VPN and selects the Enable IPSec Interface Mode option in the phase 1 settings.
Which of the following statements are correct regarding the IPSec VPN configuration?
A. To complete the VPN configuration, the administrator must manually create a virtual
IPSec interface in Web Config under System > Network.
B. Routes were automatically created based on the address objects in the firewall policies.
C. The IPSec policies must be placed at the top of the list.
D. This VPN cannot be used as part of a hub and spoke topology.
E. The virtual IPSec interface is automatically created after the phase1 configuration.
Answer: E

NEW QUESTION: 4
Refer to the exhibit.

An administrator increases the cluster RF to 3. The containers are not modified.
What will the new values in the data resiliency dashboard be for FAILURES TOLERABLE for the Zookeeper and Extent Groups components?
A. Zookeeper = 2 and Extent Groups = 1
B. Zookeeper s 2 and Extant Groups = 2
C. Zookeeper = 1 and Extent Groups = 2
D. Zookeeper - 1 and Extent Groups = 1
Answer: A