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NEW QUESTION: 1
Refer to the exhibit

the autonomous AP has a corporate and guest SSID configured . The security team requested that you limit guest user traffic to DHCP ,DNS, and web browsing on the AP.
which configuration best satisfies the request?
A. access-list 101permit udp any any eq 67 access-list 101permit udp 10.28.128
0 .255.255.255 host 10128.10.15 eq 53 access-list 101permit tcp 10.28.128 0.255.255.255 any eq 80 access-list 101deny ip any any interface dot11radio 0 ip access-group 101in
B. access-list 101 perm1t udp any any eq 67 access-list 101 per mit udp 10.28.128.0
0 .0.0.255 host 10128.10.15 eq 53 access- l1st 101 permit tcp 10.28.128.0 0.0.0.255 any eq
8 0 access-list 101 deny ip any any interface fast Ethernet 0 ip access-group 101 in
C. access-list 101 permit udp any anyeq 67 access-list 101 permit udp 10.28.128
0 .255.255.255 host 10128.10.15 eq 53 access-list 101 permit tcp 10.28.128 0.255.255.255 any eq 80 access-list 101 deny ip any any interface fast Ethernet 0 ip access-group 101 in
D. access-list 101permit udp any any eq 67 access-list 101permit udp 10.28.128.0
0 .0.0.255 host 10128.10.15 eq 53 access-list 101 permit tcp 10.28.128.0.0.0.0.255 any eq
8 0 access-list 101 deny ip any any interface dot11radio 0 ip access-group 101 in
Answer: B

NEW QUESTION: 2
You are testing an application. The application includes methods named CalculateInterest and LogLine. The CalculateInterest() method calculates loan interest. The LogLine() method sends diagnostic messages to a console window.
You have the following requirements:
The CalculateInterest() method must run for all build configurations.
The LogLine() method must be called only for debug builds.
You need to ensure that the methods run correctly.
How should you complete the relevant code? (To answer, drag the appropriate code segments to the correct locations in the answer area. Each code segment may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.)

Answer:
Explanation:

Explanation:
When the C# compiler encounters an #if directive, followed eventually by an #endif directive, it will compile the code between the directives only if the specified symbol is defined. Unlike C and C++, you cannot assign a numeric value to a symbol; the #if statement in C# is Boolean and only tests whether the symbol has been defined or not. For example,
#define DEBUG
#if DEBUG
Console.WriteLine("Debug version");
#endif

NEW QUESTION: 3
Which three attributes ate required in order to define an analysis property?
A. Property Type
B. Property Name
C. Update Size
D. Property Author
E. Property Definition
F. Report Frequency
Answer: B,E,F